2[3(x+y)-3(3x-4y)]=

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Solution for 2[3(x+y)-3(3x-4y)]= equation: 


Simplifying
2[3(x + y) + -3(3x + -4y)] = 0
2[(x * 3 + y * 3) + -3(3x + -4y)] = 0
2[(3x + 3y) + -3(3x + -4y)] = 0
2[3x + 3y + (3x * -3 + -4y * -3)] = 0
2[3x + 3y + (-9x + 12y)] = 0

Reorder the terms:
2[3x + -9x + 3y + 12y] = 0

Combine like terms: 3x + -9x = -6x
2[-6x + 3y + 12y] = 0

Combine like terms: 3y + 12y = 15y
2[-6x + 15y] = 0
[-6x * 2 + 15y * 2] = 0
[-12x + 30y] = 0

Solving
-12x + 30y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-30y' to each side of the equation.
-12x + 30y + -30y = 0 + -30y

Combine like terms: 30y + -30y = 0
-12x + 0 = 0 + -30y
-12x = 0 + -30y
Remove the zero:
-12x = -30y

Divide each side by '-12'.
x = 2.5y

Simplifying
x = 2.5y

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